Home
Class 12
MATHS
The Cartesian equation of a line is (x-5...

The Cartesian equation of a line is `(x-5)/3=(y+4)/7=(z-6)/2`, write its vector form.

Promotional Banner

Topper's Solved these Questions

  • SUPPLEMENTARY EXAM QUESTION PAPER JUNE 2018

    SUBHASH PUBLICATION|Exercise PART B|14 Videos
  • SUPPLEMENTARY EXAM QUESTION PAPER JUNE 2018

    SUBHASH PUBLICATION|Exercise PART C|14 Videos
  • SUPER MODEL QUESTIONS PAPER (WITH ANSWERS)

    SUBHASH PUBLICATION|Exercise PART-E|1 Videos
  • SUPPLEMENTARY EXAM QUESTION PAPER (WITH ANSWERS) JUNE 2016

    SUBHASH PUBLICATION|Exercise PART E|2 Videos

Similar Questions

Explore conceptually related problems

Write the vector form of the equation of the line (x-3)/3=(y+4)/7=(z-6)/2

Find the vector and the Cartesian equation of the line that passes through the points (3,-2,-5), (3,-2,6).

The image of the line (x-1)/3=(y-3)/1=(z-4)/(-5) in the plane : 2x-y+z+3=0 is the line :

Derive the equation of a plane in normal form both in the vector and Cartesian form .

Find the Cartesian equation of the line which passes through the point (-2,4,-5) and parallel to the line given by (x+3)/3=(y-4)/5=(z+8)/6 .

The equation of the plane in which the lines (x-5)/4 = (y-7)/4 = (z+3)/-5 and (x-8)/7 = (y-4)/1 = (z-5)/3 lie is

The point of intersection of the line (x-5)/3 = (y-7)/(-1) = (z+2)/1 , (x+3)/(-36) = (y-3)/2 = (z-6)/4 is