Prove that A(BC)=(AB)C

Quadrilateral ABCD is drawn to circumscribe a circle. Prove that AB+CD=AD+BC .

In Fig , ABC is a triangle in which angleABCgt90^(@) and AD bot CB, produced . Prove that AC^(2)=AB^(2)+BC^(2)+2BC.BD

In DeltaABC , AD is drawn perpendicular to BC. If BD:CD=3:1 , then prove that BC^(2)=2(AB^(2)-AC^(2)) .

In Fig . ABC is a triangle in which angleABClt90^(@)and AD botBC. Prove that AC^(2)=AB^(2)+BC^(2)-2BC.BD.

A quadrilateral ABCD is drawn to circumscribe a circle as shown. Prove that AB+CD=AD +BC.

A quadrilateral ABCD is drawn to circumscribe a circle (see Figure).Prove that AB+CD=AD+BC.

In Fig . AD is a median of a triangle ABD and AM bot BC. Prove that : AB^(2)=AD^(2)-BC.DM+((BC)/(2))^(2)

The perpendicular from A on side BC of a DeltaABC intersects BC at D such the DB = 3 CD . Prove that 2 AB^(2)=2AC^(2)+BC^(2)

In Fig . AD is a median of a triangle ABD and AM bot BC. Prove that : AC^(2)+AB^(2)=2AD^(2)+1/2 BC^(2)