What is the equation of the plane that cuts the coordinate axes at (a,0,0), (0,b,0) and (0,0,c) ?

The equation of the plane through the points (1,-1,0), (0,-2,1) and (2,0,-3) is

The intercepts of the plane 3 x+4 y-5 z-4=0 on the coordinate axes are

Find the equation of the parabola with vertex at (0,0) and focus at (0,2) .

Find the co-ordinate of a point equidistant from the four points O(0,0,0),A(a,0,0),B(0,b,0) and C(0,0,c).

The equation of the circle which touches the lines x=0, y=0 and x=c(c gt 0) is

A vector perpendicular to the plane contianing the points A(1,-1,2), B(2 , 0, -1), C(0, 2, 1) is