[" Q."f(x,y)=0" is a circle such that "f(0,lambda)=0],[" 20and "f(lambda,0)=0" have equal roots and "],[f(1,1)=-2" then the radius of the circle is "]

f(x, y) = 0 is a circle such that f(0, lambda) = 0 and f(lambda, 0)=0 have equal roots and f(1, 1)= -2 then the radius of the circle is : (A) 4 (B) 8 (C) 2 (D) 1

f(x, y) = 0 is a circle such that f(0, lambda) = 0 and f(lambda, 0)=0 have equal roots and f(1, 1)= -2 then the radius of the circle is : (A) 4 (B) 8 (C) 2 (D) 1

Let f(x,y)=0 be the equation of circle.If f(0,lambda)=0 has equal roots lambda=1,1 and f(lambda,0)=0 has roots lambda=(1)/(5),5 ,then the radius of the circle

Let f(x,y) =0 be the equation of a circle. If f (0, lamda)=0 has equal roots lamda=1,1 and f (lamda, 0 ) =0 has roots lamda =1/5 ,5, then the radius of the circle is

Let f(x,y) =0 be the equation of a circle. If f (0, lamda)=0 has equal roots lamda=1,1 and f (lamda, 0 ) =0 has roots lamda =1/2 ,2, then the centre of the circle is

Let f(x,y) =0 be the equation of a circle. If f (0, lamda)=0 has equal roots lamda=1,1 and f (lamda, 0 ) =0 has roots lamda =1/2 ,2, then the centre of the circle is

Let f(x,y)=0 be the equation of a circle. If f(0,lamda)=0 has equal roots lamda=2,2 and f(lamda,0)=0 has roots lamda=(4)/(5),5 then the centre of the circle is

Let f(x,y)=0 be the equation of a circle. If f(0,lamda)=0 has equal roots lamda=2,2 and f(lamda,0)=0 has roots lamda=(4)/(5),5 then the centre of the circle is

Let phi (x,y)=0 , be the equation of circle. If phi (0,lambda)=0 has equal roots lambda =2,2 and phi (lambda,0)=0 has roots lambda=4/5, 5 then the centre of the circle is :

Suppose f(x,y)=0 is the equation of a circle such that f(x,1)=0 has equal roots (each equal to 2) and f(1,x)=0 also has equal roots (each equal to zero). The equation of circle is