[" 其 "x=2+sin^(2)Fin d],[x^(3)-5x^(2)+33x-49]

If x=2+5i then the value of the expression x^(3)-5x^(2)+33x-49 is

int (sin ^ (2) x cos ^ (2) x) / ((sin ^ (5) x + cos ^ (3) x sin ^ (2) x + sin ^ (3) x cos ^ (2) x + cos ^ (5) x) ^ (2)) dx

If x=49 , then x^(3) - 5x^(2) - 2x - 6=?

The value of b so that x^(4) - 3x^(3) + 5x^(2) - 33x + b is divisible by x^(2) - 5x + 6 is

2cosx-cos3x-cos5x= ............... A) 16 cos ^(3) x sin ^(2) x B) 16 sin^(2) x cos ^(2) x C) 4 cos ^(2) x sin ^(2) x D) 4 sin ^(2) x cos ^(2)x

If x=2+5i then the value of the expression x^3-5x^2+33x-49 is

The value of b so that x^(4)-3x^(3)+5x^(2)-33x+b is divisible by x^(2)-5x+6 is

The value of b so that x^(4)-3x^(3)+5x^(2)-33x+b is divisible by x^(2)-5x+6 is k then sum of digits in k is

If x=2+5i (where i^(2)=-1) and 2((1)/(1!9!)+(1)/(3!7!))+(1)/(5!5!)=(2^(a))/(b!) ,then the value of (x^(3)-5x^(2)+33x-19) is equal to