(6y^(3)+11y^(2)-39y-65)" by "(3y^(2)+13y+13)

Divide each of and find the quotient and remainder: 6x^3+11 x^2-39 x-65\ b y\ 3x^2+13 x+13

3y+2(y+2)=13-(2y-5)

If the LCM of the polynomials (y -3)^(a) (2y + 1)^(b) (y + 13)^(7) and (y -3)^(4) (2y +1)^(9) (y + 13)^(c) " is " (y - 3)^(6) (2y +1)^(10) (y + 13)^(7) , then the least value of a + b +c is

I. 12x^(2)+ 11x+12 = 10x^(2) + 22x II. 13y^(2) - 18y+3=9y^(2) - 10y

Add :5m(3-m) and 6m^(2)-13m4y(3y^(2)+5y-7) and 2(y^(3)-4y^(2)+5)

If (x)/(a)=(y)/(b)=(z)/(c) , then prove that each ratio is equal to ((3x^(3)-11y^(3)+13z^(3))/(3a^(3)-11b^(3)+13c^(3)))^((1)/(3))

Solve for x and y : ( 3x )/( 2) - ( 5y )/( 3) = - 2, ( x)/(3) + ( y)/(2) = (13)/(6)

solve (3x)/(2)-(5y)/(3) = -2 (x)/(3)+(y)/(2) = 13/6

I. 2x^(2)-11x+15 = 0" "II.4y^(2)+13y+9 = 0