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Two hoses attached to separate water sources are available to fill a cyindrical swimming pool. If both hoses are used , the time it will take to fill the pool can be represented by the following equation : `(1)/(T _(1))+(1)/(T_(2))=(1)/(T_(c))`, where `T_(1) and T_(2)` represent the time needed for hoses 1 and 2 , respectively , to fill the pool on their own , and `T_(c) ` represents the time needed for hoses 1 and 2 to fill the pool working together . IF hose 1 alone can fill the pool in exactly 20 minutes and hose 2 alone can fill the pool in exactly 60 minutes , how many minutes will it take to fill the pool if both hoses work simultaneously ?

A

3

B

10

C

15

D

18

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will use the equation provided in the question: \[ \frac{1}{T_1} + \frac{1}{T_2} = \frac{1}{T_c} \] where: - \(T_1\) is the time taken by hose 1 to fill the pool on its own, - \(T_2\) is the time taken by hose 2 to fill the pool on its own, - \(T_c\) is the time taken by both hoses to fill the pool together. ### Step 1: Identify the values of \(T_1\) and \(T_2\) From the problem, we know: - Hose 1 can fill the pool in \(T_1 = 20\) minutes. - Hose 2 can fill the pool in \(T_2 = 60\) minutes. ### Step 2: Substitute the values into the equation Now, we substitute \(T_1\) and \(T_2\) into the equation: \[ \frac{1}{20} + \frac{1}{60} = \frac{1}{T_c} \] ### Step 3: Calculate the left-hand side To add the fractions \(\frac{1}{20}\) and \(\frac{1}{60}\), we need a common denominator. The least common multiple (LCM) of 20 and 60 is 60. Rewriting \(\frac{1}{20}\) with a denominator of 60: \[ \frac{1}{20} = \frac{3}{60} \] Now we can add: \[ \frac{3}{60} + \frac{1}{60} = \frac{4}{60} \] ### Step 4: Simplify the fraction Now simplify \(\frac{4}{60}\): \[ \frac{4}{60} = \frac{1}{15} \] ### Step 5: Set the equation for \(T_c\) Now we have: \[ \frac{1}{T_c} = \frac{1}{15} \] ### Step 6: Solve for \(T_c\) Taking the reciprocal of both sides gives us: \[ T_c = 15 \] ### Conclusion Thus, it will take **15 minutes** to fill the pool if both hoses work simultaneously. ---
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