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(2-4t+5t^2)-(3t^2 + 2t -7) is equivalent...

`(2-4t+5t^2)-(3t^2 + 2t -7)` is equivalent to :

A

`2t^2 - 6t + 9`

B

`2t^2 -2t + 9`

C

`2t^4 - 2t^2 -5`

D

`8t^2 -6t-5`

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The correct Answer is:
To simplify the expression \((2 - 4t + 5t^2) - (3t^2 + 2t - 7)\), we will follow these steps: ### Step 1: Write down the expression We start with the expression: \[ (2 - 4t + 5t^2) - (3t^2 + 2t - 7) \] ### Step 2: Remove the brackets When removing the brackets, we need to distribute the negative sign across the second set of parentheses: \[ 2 - 4t + 5t^2 - 3t^2 - 2t + 7 \] ### Step 3: Combine like terms Now we will combine the like terms. We will group the \(t^2\) terms, the \(t\) terms, and the constant terms: - For \(t^2\) terms: \(5t^2 - 3t^2 = 2t^2\) - For \(t\) terms: \(-4t - 2t = -6t\) - For constant terms: \(2 + 7 = 9\) Putting it all together, we have: \[ 2t^2 - 6t + 9 \] ### Final Result Thus, the simplified expression is: \[ 2t^2 - 6t + 9 \] ### Conclusion The expression \((2 - 4t + 5t^2) - (3t^2 + 2t - 7)\) is equivalent to \(2t^2 - 6t + 9\), which corresponds to option 1. ---
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