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What is the value of 8/(y^2)-(x^2)/(y)...

What is the value of `8/(y^2)-(x^2)/(y)` when =-3 and y=-4 ?

A

`-11/4`

B

`-7/4`

C

`7/4`

D

`11/4`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \( \frac{8}{y^2} - \frac{x^2}{y} \) when \( x = -3 \) and \( y = -4 \), we will follow these steps: ### Step 1: Substitute the values of \( x \) and \( y \) We start by substituting \( x = -3 \) and \( y = -4 \) into the expression. \[ \frac{8}{(-4)^2} - \frac{(-3)^2}{-4} \] ### Step 2: Calculate \( y^2 \) and \( x^2 \) Next, we calculate \( (-4)^2 \) and \( (-3)^2 \): \[ (-4)^2 = 16 \quad \text{and} \quad (-3)^2 = 9 \] ### Step 3: Substitute the calculated values back into the expression Now we substitute these values back into the expression: \[ \frac{8}{16} - \frac{9}{-4} \] ### Step 4: Simplify the fractions Now we simplify \( \frac{8}{16} \) and \( \frac{9}{-4} \): \[ \frac{8}{16} = \frac{1}{2} \quad \text{and} \quad \frac{9}{-4} = -\frac{9}{4} \] ### Step 5: Combine the fractions Now we combine the two fractions: \[ \frac{1}{2} - \left(-\frac{9}{4}\right) = \frac{1}{2} + \frac{9}{4} \] ### Step 6: Find a common denominator The common denominator between 2 and 4 is 4. We convert \( \frac{1}{2} \) to have a denominator of 4: \[ \frac{1}{2} = \frac{2}{4} \] ### Step 7: Add the fractions Now we can add the two fractions: \[ \frac{2}{4} + \frac{9}{4} = \frac{2 + 9}{4} = \frac{11}{4} \] ### Final Answer Thus, the value of the expression \( \frac{8}{y^2} - \frac{x^2}{y} \) when \( x = -3 \) and \( y = -4 \) is: \[ \frac{11}{4} \] ---
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