e^(sec^(2)x)+3cos^(2)alpha

Differentiable the following w.r.t. x : e^(sec^(2)x)+3cos^(-1)x .

Differentiate the following w.r.t. x : e^(sec^(2)x)+3cos^(-1)x .

If sec^(2)alpha+cos^(2)alpha=2 , then find the value of sec alpha+ cos alpha .

For alpha ne 0, " if "cos(theta+alpha), costheta " and "cos(theta-alpha) are in harmonic progression, then sec^(2)theta*cos^(2)""alpha/2=

((1)/(sec^(2)alpha-cos^(2)alpha)+(1)/(cos ec^(2)alpha-sin^(2)alpha))cos^(2)alpha*sin^(2)alpha=(1-cos^(2)alpha*sin^(2)alpha)/(2+cos^(2)alpha*sin^(2)alpha)

To prove ((1)/(sec^(2)alpha-cos^(2)alpha)+(1)/(cos ec^(2)alpha-sin^(2)alpha))cos^(2)alpha sin^(2)alpha=(1-sin^(2)alpha cos^(2)alpha)/(2+sin^(2)alpha cos^(2)alpha)

Solve the following equations: a) 3sinx+2cos^(2)x=0 , b) sec^(2)2alpha=1-tan2alpha

(1)/(sec^(4)alpha)+(1)/(cos ec^(4)alpha)+(2)/(sec^(2)alpha+cos ec^(2)alpha)=? and (cos A)/(1+sin A)+(1+sin A)/(cos A)=?

(1)/(sec^(4)alpha)+(1)/(cos ec^(4)alpha)+(2)/(sec^(2)alpha+cos ec^(2)alpha)=? and (cos A)/(1+sin A)+(1+sin A)/(cos A)=?