The three vertices of a parallelogram taken in order are `-1,0),(3,1)a n d(2,2)` respectively. Find the coordinates of the fourth vertex.

Explanation

Let A(-1, 0), B(3, 1), C(2, 2) and D(x, y) be the vertices of a parallelogram ABCD taken in order.


Since, the diagonals of a parallelogram bisect each other.



Then, Coordinates of the mid-point of AC=Coordinates of the mid-point of BD


`((-1+2)/2,(0+2)/2)=((3+x)/2, (1+y)/2)`
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