" 3.Is "|x+1|" differentiable at "x=-1?

Show that, the function f(x) = |x-1| is not differentiable at x = 1

f(x)={ax^(2)-b,, if |x| =1 is differentiable at x=1, find a,bquad if |x|>=1

find the values of a and b , such that f(x) ={ax^2+1,xle1 and x^2+ax+b , x gt1 is differentiable at x=1

find the values of a and b , such that f(x) ={ax^2+1,xle1 and x^2+ax+b , x gt1 is differentiable at x=1

Find the values of a and b , if the function f defined by f(x)={x^2+3x+a ; if xlt=1, b x+2 ; if x >1 is differentiable at x=1

Statement-1 : Condition of Lagrange's mean value theorem fail in f(x) = | x-1 | (x-1) . Statement-2 : |x-1| is not differentiable at x=1 .

Prove that f(x)=|x+1| is not differentiable at x=-1

Find the values of a and b if f(x)={a+sin^(-1)(x+b), xgeq1 and x ,x<1 is differentiable at x=1.

Find the values of a and b if f(x)={a+sin^(-1)(x+b),xgeq1 and x ,x<1 is differentiable at x=1.

Find the values of a and b if f(x)={a+sin^(-1)(x+b), xgeq1 and x ,x<1 is differentiable at x=1.