[quad Delta=|[a,b,a alpha+b],[b,c,b alpha+c],[a alpha+b,b alpha+c,0]|" is "]

If det[[a,b,a alpha+bb,c,b alpha+ca alpha+b,b alpha+c,0]]=0 then

If the determinant |[a,b,2a alpha+3b],[b,c,2b alpha+3 c],[2a alpha+3b,2b alpha+3c,0]|=0 then

If |(a,b,a alpha+b),(b,c, b alpha+c),(a alpha+b, b alpha+c,0)|=0 then

If |{:(a,b,a alpha+b),(b,c,b alpha+c),(a alpha +b,b alpha+c,0):}|=0 Prove that a,b,c are in G.P. or alpha is a root of ax^2 + 2bx + c=0

The determinant Delta = |(b,c,b alpha +c),(c,d,c alpha + d),(b alpha + c,c alpha + d,a a^(3) - c alpha)| is equal to zero, if

The determinant Delta = |(b,c,b alpha +c),(c,d,c alpha + d),(b alpha + c,c alpha + d,a a^(3) - c alpha)| is equal to zero, if

The system of equations ax+by+(a alpha+ b)z=0 bx+cy+(b alpha+c)z=0 (a alpha+b)x+(balpha+c)y=0 has a non zero solutions if a,b,c are in

Given that a alpha^(2)+2b alpha+c!=0 and that the system of equations (a alpha+b)x+alpha y+bz=0,(b alpha+c)x+by+cz=0,(a alpha+b)y+(b alpha+c)z=0 has a non trivial solution,then a ,b,c are in

If Delta_(1) is the area of the triangle with vertices (0, 0), (a tan alpha, b cot alpha), (a sin alpha, b cos alpha), Delta_(2) is the area of the triangle with vertices (a sec^(2) alpha, b cos ec^(2) alpha), (a + a sin^(2)alpha, b + b cos^(2)alpha) and Delta_(3) is the area of the triangle with vertices (0,0), (a tan alpha, -b cot alpha), (a sin alpha, b cos alpha) . Show that there is no value of alpha for which Delta_(1), Delta_(2) and Delta_(3) are in GP.