If `sintheta=(a^2-b^2)/(a^2+b^2)` , find the values of other five trigonometric ratios.

Explanation

`sinθ= (a^2−b^2)/( a^2+b^2)`


`cosθ=sqrt[(a^2+b^2)^2-(a^2−b^2)^2]/[(a^2+b^2)^2]=sqrt[4a^2b^2]/[a^2+b^2]=(2ab)/[ a^2+b^2]`


`tanθ=(a^2−b^2)/(2ab)`


`secθ=(a^2+b^2)/(2ab)`


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