" (iii) "x+(c+1)y=5*(c+1)x+9y=8c-1

If circle x (x -1) + y (y -1) = c(x + y -1) touches X-axis , then c =

The solution of ((dy)/(dx))^(2)+(2x+y)(dy)/(dx)+2xy=0, is (i) (y+x^(2)-c_(1))(x+log y+y^(2)+c_(2))( (ii) (y+x^(2)-c_(1))(x-log y-c_(2))( iii) (y+x^(2)-c_(1))(x+log y-c_(2))( iv) (y+x^(2)-c_(1))(3x+log y-c_(2))

(x-1)dy-(1+y)dx=0, y=4" if " x=2 A) 5(x-1)(1+y)=1 B) (x-1)(1+y)=5 C) 1+y=5(x-1) D) 5(1+y)=x-1

y^(2)-(dy)/(dx)=x^(2)(dy)/(dx) A) y^(-1)+tan^(-1)x=c B) x^(-1)+tan^(-1)y=c C) y+tan^(-1)x=c D) x^(-1)+y^(-1)=tan^(-1)x+c

(e^(y)+1)cos x dx+e^(y)sin x dy =0 A) (e^(y)+1)sin x =c B) (e^(y)+1)=c tan x C) e^(y)sin x + cos x=c D) (e^(x)+1)sin y=c

Find the point of intersection of the following pair of lines : (i) 9x-10y=12 and 2x-5=0 (ii) y=m_(1)x+c_(1) and y=m_(2)x+c_(2) (iii) x+y=8 and x-y=2

Find the point of intersection of the following pair of lines : (i) 9x-10y=12 and 2x-5=0 (ii) y=m_(1)x+c_(1) and y=m_(2)x+c_(2) (iii) x+y=8 and x-y=2

The equation of the tangent to the curve x = (t - 1)/(t + 1), y = (t + 1)/(t - 1) at t = 2 is a) x + 9y - 6 = 0 b) 9x - y - 6 = 0 c) 9x + y + 6 = 0 d) 9x + y - 6 = 0

(dy)/(dx)=(xy)/((1-x)(1+y)) A) x+y+log[y(1-x)]=c B) x+y+log[x(1-y)]=c C) x+y+log(x+y)=c D) y-x+log[x(1-y)]=c

If x-y=1 and x^(2)+y^(2)=41, then the value of x+y will be (a)5 or 4(b)-5 or -4 (c) +-9(d)+-1