Range of `sin^(-1)x` is

A

`[0,pi/2]`

B

`[0,pi]`

C

`[-pi/2,pi/2]`

D

none of these

Verified by Experts

The correct Answer is:

C

Similar Questions

Explore conceptually related problems

Range of sin^(-1)x-cos^(-1)x is

Range of sin^(-1)x+cos^(-1)x+tan^(-1)x is

Range of sin^(-1)x+cos^(-1)x+tan^(-1)x is [a pi,b pi] ,then the value of a+b=

Range of sin^(-1)x+cos^(-1)x+tan^(-1)x is [a pi, b pi] then the value of a+b =

Range of sin^(-1)x+cos^(-1)x+tan^(-1)x is [a pi,b pi], then the value of a

Range of f(x)=sin^(-1)x*sin x

Range of f(x)=sin^(-1)x+sec^(-1)x is

Range of f(x)=sin^(-1)x+tan^(-1)x+sqrt(x+1) is [a,b] then b+a is equal to

Range of f(x)=sin^(-1)x+cos^(-1)x+cot^(-1)x