Pulley system

The moment of inertia of the pulleys system as shown in the figure-5.103 is 4 kgm^(2) The radii of bigger and smaller pulleys 2 mand 1m respectively.The angular acceleration of the pulley system is: (take = 10 m//s^(2) )

In the pulley system shown the two upper pulleys are fastened together to form single unit. The cable is wrapped around the smaller pulley with its end secured to the pulleys so that it cannot slip. Determine the upward acceleration of block B if A has downward acceleration of 2 m//s^(2) :

A step pulley system is shown in figure-2.50. Find the relation in masses m and M for which the system remain in equilibrium. Assume string will not slide over the pulleys. ((r_(1))/(r_(2))=(1)/(2),(r_(3))/(r_(4))=(3)/(4)) [(M)/(m)=(3)/(8)sintheta]

Consider the stituation shown in figure. The elevator is going up with an acceleration of 2.00 ms^-2 and the focal length of the mirror is 12.0 cm. All the surfaces are smooth and the pulley is light. The mass-pulley system is released from rest (with respect to the elevator) at t=0 when the distance of B from the mirror is 42.0 cm. Find the distance between the image of the block B and the mirror at t=0.200 s. Take g=10 ms^-2

Pulley mas system || Toppling

A rigid massless beam is balanced by a particle of mass 4m in left hand side and a pulley particle system in right hand side. The value of x/y is

In the fig. m_(2) gt m_(1) . Pulley and string and massless and Pulley is smooth. The system is released from rest. After 2 seconds of motion m_(2) was held with the hand.

In an ideal pulley particle system, mass m_2 is connected with a vertical spring of stiffness k . If mass m_2 is released from rest, when the spring is underformed, find the maximum compression of the spring.

Whole system shown is at rest. Pulley and string are massless. Net force on the pulley by the string is?