" e "R,a!=0" and the quadratic equation "ax^(2)-bx+1=0" has imaginary roots,then "a+b+1" is: "

If a,b in R,a!=0 and the quadratic equation ax^(2)-bx+1=0 has imaginary roots,then (a+b+1) is a.positive b.negative c.zero d. Dependent on the sign of b

If a ,b in R ,a!=0 and the quadratic equation a x^2-b x+1=0 has imaginary roots, then (a+b+1) is a. positive b. negative c. zero d. Dependent on the sign of b

If a ,b in R ,a!=0 and the quadratic equation a x^2-b x+1=0 has imaginary roots, then (a+b+1) is a. positive b. negative c. zero d. Dependent on the sign of b

If a ,b in R ,a!=0 and the quadratic equation a x^2-b x+1=0 has imaginary roots, then (a+b+1) is a. positive b. negative c. zero d. Dependent on the sign of b

a,b,c in R,a!=0 and the quadratic equation ax^(2)+bx+c=0 has no real roots,then

a, b, c in R, a!= 0 and the quadratic equation ax^2+bx+c=0 has no real roots, then

a, b, c in R, a!= 0 and the quadratic equation ax^2+bx+c=0 has no real roots, then

The quadratic equation ax^(2)+bx+c=0 has real roots if:

The quadratic equation ax^(2)+bx+c=0 has real roots if: