1" add "2sqrt(2)+5sqrt(3)" and "sqrt(2)-3sqrt(3)

Add (3sqrt(2) + 7 sqrt(3)) and (sqrt(2) - 5sqrt(3)) .

Add 2sqrt2+ 5sqrt3 and sqrt2- 3sqrt 3 .

Add and and sqrt(2)-3sqrt(3)

Add 2sqrt2+5sqrt3 and sqrt2-3sqrt2

Add 2sqrt2+5sqrt3 and sqrt2 - 3 sqrt3

Do as directed: (i) Add : sqrt(125 + 2 sqrt(27) and - 5 sqrt(5) - sqrt(3) (ii) Add: sqrt(7) - sqrt(11) and sqrt(5) - sqrt(11) + sqrt(13) (iii) Multiply : 2 sqrt(2) by 5 sqrt(2) (iv) Multiply : (-3 + sqrt(5)) by 3 (v) Divide : 7 sqrt(5) by - 14 sqrt(125) Divide : 7 sqrt(5) by -14 sqrt(125) (vi) Divide : 2 sqrt(216) - 3 sqrt(27) by 3

Add (i) (2sqrt(3)-5sqrt(2)) and (sqrt(3) + 2sqrt(2)) (ii) (2sqrt(2) + 5sqrt(3) - 7 sqrt(5) and (3sqrt(3)-sqrt(2) + sqrt(5)) (iii) ((2)/(3) sqrt(7) -(1)/(2)sqrt(2)+6sqrt(11)) and ((1)/(3)sqrt(7) + (3)/(2)-sqrt(11))

The simplest rationalising factor of 2sqrt(5)-sqrt(3) is (a) 2sqrt(5)+\ 3 (b) 2sqrt(5)+sqrt(3) (c) sqrt(5)+sqrt(3)\ \ (d) sqrt(5)-sqrt(3)

If both a and b are rational numbers,find the values of a and b in each of the following equalities :(sqrt(3)-1)/(sqrt(3)+1)=a+b sqrt(3)( ii) (3+sqrt(7))/(3-sqrt(7))=a+b sqrt(7)(5+2sqrt(3))/(7+4sqrt(3))=a+b sqrt(3)( iv) (5+sqrt(3))/(7-sqrt(3))=47a+sqrt(3)b(sqrt(5)+sqrt(3))/(sqrt(5)-sqrt(3))=a+b sqrt(15) (iv) (sqrt(2)+sqrt(3))/(3sqrt(2)-2sqrt(3))=1-b sqrt(3)

If a = (sqrt(3) - sqrt(2))/(sqrt(3) + sqrt(2)) and b = (sqrt(3) + sqrt(2))/(sqrt(3) - sqrt(2)) then value of sqrt(3a^2 - 5ab + 3b^2) is