Sum of the areas of two squares is `468m^2.` If the difference of their perimeters is `24m`, formulate the quadratic equation to find the sides of the two squares.

Explanation

Let the side of the first square be 'a'm and that of the second be 'A' `m`.

Area of the first square `=a^{2}` sq `m`.

Area of the second square `=A^{2}` sq `m`.

Their perimeters would be `4 a` and `4 ~A` respectively.

Given `4 ~A-4 a=24`


`A-a=6-(1) `

`A^{2}+a^{2}=468-(2)`

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