If `cos e cA=2,` find the value of `1/(tanA)+(sinA)/(1+cosA)`

Explanation

`CosecA=frac{text { hypotenuse }}{text { opposite side }}=frac{2}{1}`

Let `x` be the adjacent side

By applying Pythagoras theorem


`A C^{2}=A B^{2}+B C^{2} `

`4=1+x^{2} `

`x^{2}=3 Rightarrow x=sqrt{3} `

`Sin A=frac{1}{ cosec A}=frac{1}{2} `

...