`(1+tan alpha tan beta)^2 + (tan alpha - tan beta)^2 =`

(1+ tan alpha tan beta)^(2) + (tan beta - tan beta)^(2)=

Prove the following identity: (1+tan alpha tan beta)^(2)+(tan alpha)(tan alpha-tan beta)^(2)=sec^(2)alpha sec^(2)beta

(tan alpha + tan beta )/( tan (alpha + beta ))+(tan alpha - tan beta )/(tan (alpha - beta )) =

sin alpha + sin beta = a "and" cos alpha + cos beta = b (tan alpha + tan beta)/(1-tan alpha tan beta)=

If alpha+ beta + gamma=90^(@) , then tan alpha+ tan beta + tan alpha tan beta cot gamma is __________

If tan theta=(tan alpha+tan beta)/(1+tan alpha tan beta) then show that sin2 theta=(sin2 alpha+sin2 beta)/(1+sin2 alpha sin2 beta)

(sec alpha * sec beta + tan alpha tan beta )^(2)-( sec alpha * tan beta + tan alpha * sec beta )^(2) =

If tan alpha=(1-cos beta)/(sin beta), then a )tan3 alpha=tan2 beta(b)tan2 alpha=tan beta(c)tan2 beta=tan alpha(d) none of these

If tan (alpha + beta) = 2 and tan (alpha - beta) = 1, then tan (2 alpha ) is equal to:

If 2 tan^2 alpha tan^2 beta tan^2 gamma+ tan^2 alpha tan^2 beta+ tan^2 beta tan^2 gamma+ tan^2 gamma tan^2 alpha=1 , prove that sin^2 alpha+ sin^2 beta+ sin^2 gamma =1 .