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If A + B is 90^@, then ( tan A. tan B +...

If A + B is `90^@`, then ` ( tan A. tan B + tan A. cot B)/ (Sin A. Sec B) - sin^2 B/ cos^2 A` is equal to:

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`A + B = 90° `
`=> A = 90 – B`
So `Tan A = Cot (90^@ - A) = Cot B`
So `Tan B = Cot (90^@ - B) = Cot A`
...
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