`A(3,2)a n dB(-2,1)` are two vertices of a triangle ABC whose centroid G has the coordinates `(5/3,-1/3)dot` Find the coordinates of the third vertex C of the triangle.

Explanation

Let `A(3,2),B(−2,1) and C(x,y)` be the coordintes of a triangle.


Centroid(5/2,−1/3)=((3−2+x)/3)2,(2+1+y)/3)`


Equating the x−co-ordiantes and y−co-ordinates we get
`((1+x))/3 =5/2`


Or, 2+2x=15
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