Three consecutive positive integers are such that the sum of the square of the first and the product of other two is 46, find the integers.

Explanation

Let the numbers are `x,x+1,x+2`

Now,

`x^2+(x+1)(x+2)=46`

`=>x^2+x^2+2x+x+2=46`

`=>2x2+3x−44=0`


`=>(x+(22)/4)(x-4)=0`

So,

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