In a right triangle `B C` , right angled at `B ,` the ratio of `A BtoA C` is `1:sqrt(2)` . Find the values of `(2tanA)/(1+tan^2A)` and (ii) `(2tanA)/(1-tan^2A)`

Explanation

Given,

`AB : AC = 1 : sqrt2
`

`​=>(AB)/(AC)​=1/(sqrt2)`
​​

So, `AB = x` and `AC = sqrt2x`

By Pythagoras theorem, we have

`(AC)^2=(AB)^2+(BC)^2`

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