If `sectheta+tantheta=p ,` show that `(p^2-1)/(p^2+1)=sintheta`

Explanation

To prove that \(\frac{p^2 - 1}{p^2 + 1} = \sin \theta\) given that \( \sec \theta + \tan \theta = p\), we will start from the left-hand side (LHS) and manipulate it step by step.

### Step-by-Step Solution:

1. **Start with the left-hand side:**
\[ \text{LHS} = \frac{p^2 - 1}{p^2 + 1} \]
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