If `sintheta+costheta=pa n dsectheta+cos e ctheta=q ,` show that `q(p^2-1)=2pdot`

Explanation

To prove that \( q(p^2 - 1) = 2p \) given that \( \sin \theta + \cos \theta = p \) and \( \sec \theta + \csc \theta = q \), we will follow these steps:

### Step 1: Express \( p^2 \)
We start with the expression for \( p \):
\[ p = \sin \theta + \cos \theta \]
Now, we will square both sides:
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