Home
Class 10
MATHS
The line segment joining the points P(3,...

The line segment joining the points `P(3,3)a n dQ(6,-6)` is trisected at the points A and B such that A is nearer to P. If A also lies on the line given by `2x+y+k=0,` find the value of `kdot`

Promotional Banner

Topper's Solved these Questions

  • CONSTRUCTIONS

    RD SHARMA|Exercise All Questions|21 Videos

  • PAIR OF LINEAR EQUATIONS IN TWO VARIABLES

    RD SHARMA|Exercise All Questions|390 Videos

Similar Questions

Explore conceptually related problems

The line segment joining points A(2,1) and B(5,-8) is trisected at the points P and Q such that P is nearer to A. If P also lies on the line given by 2x -y + K = 0, find the value of k.

The line segment joining the points A(3,2) and B (5,1) is divided at the point P in the ratio 1 : 2 and it lies on the line 3x-18y+k=0 . Find the value of k.

The line segment joining the points A(3, -4) and B(1, 2) is trisected at the points P(p, -2) and Q((5)/(3), q) . Find the values of p and q.

The line joining the points (2,1) and (5,-8) is trisected at the points P and Q. If point P lies on the line 2x-y+k=0. Find the value of k.

The line segment joining the points (3, -4) and (1, 2) is trisected at the points P and Q. If the co-ordinates of P and Q are (p,-2) and ((5)/(3), q) respectively, find the values of p and q.

The line segment joining the points (3,-4) and (1,2) is trisected at the points P and Q If the coordinates of P and Q are (p,-2) and (5/3,q) respectively.Find the values of p and q.

If the line segment joining the points (3, 4) and (7, 7) passes through the point (k, 0), then find the value of k.

Point P divides the line segment joining the points A(2,1)and B(5,-8) such that (AP)/(AB)=1/3. If P lies on the line 2x - y + k =0, find the value of k.

Point P divides the lne segment joning the points A (2,1) and B(5,-8) such that (AP)/(AB)=1/3 . If P lies on the line 2x - y + k = 0 , find the value of k

RD SHARMA-COORDINATE GEOMETRY-All Questions
  1. If G be the centroid of a triangle ABC, prove that, AB^2 + BC^2 + CA...

    Text Solution

    |

  2. If A(-3,5),B(-2,-7),C(1,-8)a n dD(6,3) are the vertices of a quadrilat...

    Text Solution

    |

  3. The line segment joining the points P(3,3)a n dQ(6,-6) is trisected at...

    Text Solution

    |

  4. If the area of A B C formed by A(x , y),B(1,2)a n dC(2,1) is 6 squae ...

    Text Solution

    |

  5. Show that the points (a , a),(-a ,-a) and (-sqrt(3)a ,sqrt(3)a) are th...

    Text Solution

    |

  6. The x-coordinate of a point P is twice its y-coordinate. If P is eq...

    Text Solution

    |

  7. If A(4,-6),B(3,-2)a n dC(5,2) are the vertices of A B C , then verify...

    Text Solution

    |

  8. Three vertices of a parallelogram ABCD are A(3,-4),B(-1,-3)a n dC(-6,2...

    Text Solution

    |

  9. The base PQ of two equilateral triangles PQR and PQR’ with side 2a lie...

    Text Solution

    |

  10. Let ABCD be a square of side 2a. Find the coordinates of the vertices ...

    Text Solution

    |

  11. Find the coordinates of the vertices of an equilateral triangle of sid...

    Text Solution

    |

  12. The area of the triangle formed by (a , b+c),(b , c+a)a n d(c , a+b) ...

    Text Solution

    |

  13. If the points A(4,3)a n dB(x ,5) are on the circle with centre O(2,3),...

    Text Solution

    |

  14. Find the equation of the perpendicular bisector of AB, where A and B ...

    Text Solution

    |

  15. If the point (x , y) is equidistant from the points (a+b , b-a) and ...

    Text Solution

    |

  16. Find the distance between the points: P(-6,7) andQ(-1,-5) R(a+b , a-b...

    Text Solution

    |

  17. Find the angle subtended at the origin by the line segment whose end ...

    Text Solution

    |

  18. Prove that the points (2,3),(-4,-6)a n d(1,3/2) do not form a triangle...

    Text Solution

    |

  19. Show that the points (-3,2),(-5,-5),(2,-3) and (4,4) are the vertices...

    Text Solution

    |

  20. Q.7 The two opposite vertices of a square are (l.-6)and (5,4). Find th...

    Text Solution

    |