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If `tanA=1` and ` tanB=sqrt(3),e v a l u a t ecosAcosB-sinAsinBdot`

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To solve the problem, we need to evaluate the expression \( \cos A \cos B - \sin A \sin B \) given that \( \tan A = 1 \) and \( \tan B = \sqrt{3} \). ### Step-by-Step Solution: 1. **Identify the angles A and B:** - We know that \( \tan A = 1 \). The angle whose tangent is 1 is \( 45^\circ \). Therefore, \( A = 45^\circ \). - We also know that \( \tan B = \sqrt{3} \). The angle whose tangent is \( \sqrt{3} \) is \( 60^\circ \). Therefore, \( B = 60^\circ \). ...
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RD SHARMA-TRIGONOMETRIC RATIOS-All Questions
  1. Find the value of theta in each of the following: (i)2sin2theta=sqrt...

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  2. An equilateral triangle is inscribed in a circle of radius 6 cm. Find ...

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  3. If tanA=1 and tanB=sqrt(3),e v a l u a t ecosAcosB-sinAsinBdot

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  4. Find(sin18^0)/(cos72^0)+(sin22^0)/(cos68^0)-(cos38^0cos e c52^0)/(tan1...

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  5. If s e c4A=cos e c(A-20^@) , where 4A is an acute angle, find the ...

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  6. Evaluate each of the following: (a) cos(40^0-theta)-sin(50^0+theta)...

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  7. Evaluate : 4(sin^4 30^0+cos^4 60^0)-2/3(sin^2 60^0-cos^2 45^0)+1/2tan...

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  8. Evaluate : (sin50^0)/(cos40^0)+(cos e c40^0)/(sec50^0)-4cos50^0cos e ...

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  9. Evaluate : tan35^0tan40^0tan45^0tan50^0tan55^0

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  10. Evaluate : cos e c(65^0+theta)-sec(25^0-theta)-tan(55^0-theta)+cot(...

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  11. Evaluate : tan7^0tan23^0tan60^0tan67^0tan83^0

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  12. Evaluate : (2sin68^0)/(cos22^0)-(2cot15^0)/(5tan75^0)-(3tan45^0tan20^...

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  13. Evaluate : ((3cos55^0) / (7sin35^0))-(4/7)(cos70^0cos e c20^0)/(tan5^0...

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  14. Prove the following: (cos(90^0-theta)sec(90^0-theta)t a ntheta)/(cos ...

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  15. Prove the following: (tan(90^0-A)cotA)/(cos e c^2A)-cos^2A=0

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  16. Prove the following: sinthetasin(90^0-theta)-costhetacos(90^0-theta)=...

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  17. In a /\A B C , right angled at B , if A B=4 and B C=3 , find all t...

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  18. In a /\A B C , right angled at B , if A B=12 and B C=5 , find: (i) ...

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  19. If sinA=3/5 , find cosA and tanA .

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  20. If costheta=8/(17) , find the other five trigonometric ratios.

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