[" If "24.125=24+(A)/(10)+(B)/(100)+(C)/(1000)," then "A+B+C=],[[" (a) "3," ,"]]

If 24.125=24+(A)/(10)+(B)/(100)+(C)/(1000), then A+B+C=3( b) 613(d)8

(10)^(24)xx(10)^(-21)=?3b.10c.100d.1000

(a) 543.24 (b) 49 (c) 16 (d) 37 (a) 38 (c)

Convert the fractions into a decimal: a. (17)/(10) b. (239)/(100) c. (2103)/(100) d. (3001)/(1000)

If log_(10) x+log_(10) y= 3 and log_(10) x-log_(10) y=1, then x and y are respectively a. 10 and 100 b. 100 and 10 c. 1000 and 100 d. 100 and 1000

If n(A xx B) = 24, n(B xx C) = 36 , and n(B) = 3 , then n(A xx C) =

(6^(-1)-8^(-1))^(-1) = (a) 1/(24) (b) 24 (c) -24 (d) -1/(24)

8, 27, 64, 100, 125, 216, 343 (a) 27 (b) 100 (c) 125 (d) 343

55% of 1000-:60% of 2000=(11)/(24) (b) (12)/(25)(13)/(24) (d) (14)/(25)