`(2p+1)sinalpha=2p(p+1)cos alpha => sin alpha=` 1) `(2p+1)/(2p^2+2p+1)` 2) `(2p+3)/(2p^2+2p+1)` 3) `(2p(p+1))/(2p^2+2p+1)` 4)1

Expand : (2p-1/(2p))^3

4p−(3p−1​)=1−(2p−2​)

If the line x cos alpha+y sin alpha=p touches the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 ,then the point of contact will be ((-a^(2)cos alpha)/(p),(-b^(2)sin alpha)/(p)) ((b^(2)cos alpha)/(p),(a^(2)sin alpha)/(p)) ((b^(2)sin alpha)/(p),(a^(2)cos alpha)/(p)) ( (a^(2)cos alpha)/(p),(b^(2)sin alpha)/(p))

If p sin (alpha+ beta)= cos (alpha-beta) , then show that (1)/(1- p sin2 alpha)+(1)/(1-p sin 2 beta)=(2)/(1-p^(2)) .

If (2p)/(p^(2)-2p+1)=(1)/(4),p!=0, then the value of p+(1)/(p)

If sec theta + tan theta =p, then tan theta is equal to ............... A) (2p)/(p^(2) -1) B) (p^(2) -1)/(2p) C) (p^(2) +1)/(2p) D) (2p)/(p^(2)+1)