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One year ago, a man was 8 times as old a...

One year ago, a man was 8 times as old as his son. Now his age is equal to the square of his son’s age. Find their present ages.

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To solve the problem step by step, we need to define the variables and set up the equations based on the information given. ### Step 1: Define the Variables Let: - \( X \) = Present age of the man - \( Y \) = Present age of the son ### Step 2: Set Up the Equations ...
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RD SHARMA-QUADRATIC EQUATIONS-All Questions
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  2. The product of Ramu's age (in years) five years ago with his age (in ...

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  3. One year ago, a man was 8 times as old as his son. Now his age is equa...

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  10. Solve for: 4/x-3=5/(2x+3),x!=0,,-3/2

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  11. Solve for: (x-4)/(x-5)+(x-6)/(-x-7)=10/3; x!=5,7

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  12. Solve for : (5+x)/(5-x)-(5-x)/(5+x)=3 3/4; x!=5,-5

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  13. Solve for : 3/(x+1)-1/2=2/(3x-1),x!=3/5,-1/7

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  14. Solve for : 2/(x+1)+3/(2(x-2))=(23)/(5x);x!=0,-1,2

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  19. Find the roots of the quadratic equations (if they exist) by the metho...

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  20. If the roots of the equation x^2+2c x+a b=0 are real unequal, prove th...

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