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There are two values of time for which a...

There are two values of time for which a projectile is at the same height. The sum of these two times is equal to (T = time of flight of the projectile)

A

`(3T)/(2)`

B

`(4T)/(2)`

C

`(3T)/(4)`

D

T

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the sum of the two times (t1 and t2) at which a projectile is at the same height, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Projectile Motion**: A projectile follows a parabolic trajectory. It reaches the same height at two different times during its flight: once while ascending and once while descending. 2. **Time of Flight**: The total time of flight (T) for a projectile launched vertically with an initial velocity \( u_y \) is given by the formula: \[ T = \frac{2u_y}{g} \] where \( g \) is the acceleration due to gravity. 3. **Identifying the Heights**: Let’s denote the height at which the projectile is at the same height as \( h \). The projectile will reach this height at two different times, \( t_1 \) and \( t_2 \). 4. **Using the Equation of Motion**: The vertical motion can be described by the equation: \[ h = u_y t - \frac{1}{2} g t^2 \] We can set this equation for both times \( t_1 \) and \( t_2 \): \[ h = u_y t_1 - \frac{1}{2} g t_1^2 \] \[ h = u_y t_2 - \frac{1}{2} g t_2^2 \] 5. **Setting Up the Equations**: Rearranging both equations gives us: \[ \frac{1}{2} g t_1^2 - u_y t_1 + h = 0 \] \[ \frac{1}{2} g t_2^2 - u_y t_2 + h = 0 \] 6. **Using the Quadratic Formula**: The above equations are quadratic in form. The sum of the roots of a quadratic equation \( ax^2 + bx + c = 0 \) is given by \( -\frac{b}{a} \). For our equations: - \( a = \frac{1}{2} g \) - \( b = -u_y \) Thus, the sum of the times \( t_1 + t_2 \) is: \[ t_1 + t_2 = -\frac{-u_y}{\frac{1}{2} g} = \frac{2u_y}{g} \] 7. **Relating to Time of Flight**: From our earlier step, we know that: \[ T = \frac{2u_y}{g} \] Therefore, we can conclude that: \[ t_1 + t_2 = T \] ### Final Answer: The sum of the two times \( t_1 + t_2 \) for which the projectile is at the same height is equal to the total time of flight \( T \). ---
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