A man slides down on a telegraphic pole ...

A man slides down on a telegraphic pole with an acceleration equal to one-fourth of acceleration due to gravity.The frictional force between man and pole is equal to (in terms of man's weight `W`)

A

`( w)/( 4)`

B

`( w)/( 2)`

C

`( 3w)/( 4)`

D

w

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The correct Answer is:

3

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