An object is moving on a plane surface with uniform velocity `10ms^(-1)` in presence of a force 10N. The frictional force between the object and the surface is

Options

A. 1N
B. `-10N`
C. 10N
D. 100N

Answer

To solve the problem, we need to analyze the forces acting on the object moving on a plane surface with a uniform velocity of \(10 \, \text{m/s}\) in the presence of a force of \(10 \, \text{N}\).

### Step-by-Step Solution:

1. **Understand the Situation**: The object is moving with a uniform velocity, which means that its speed is constant. According to Newton's first law of motion, if an object is moving with a constant velocity, the net force acting on it must be zero.

2. **Identify the Forces**: There are two main forces acting on the object:
- The applied force (\(F_{\text{applied}}\)) of \(10 \, \text{N}\) in the direction of motion.
- The frictional force (\(F_{\text{friction}}\)) acting in the opposite direction of motion.

3. **Set Up the Equation for Net Force**: Since the object is moving with a uniform velocity, the net force acting on it is zero. Therefore, we can write the equation:
\[ F_{\text{applied}} - F_{\text{friction}} = 0 \]

4. **Substitute the Known Values**: We know that the applied force is \(10 \, \text{N}\). Substituting this into the equation gives:
\[ 10 \, \text{N} - F_{\text{friction}} = 0 \]

5. **Solve for the Frictional Force**: Rearranging the equation to solve for the frictional force gives:
\[ F_{\text{friction}} = 10 \, \text{N} \]

6. **Direction of the Frictional Force**: The frictional force acts in the opposite direction to the applied force, but its magnitude is \(10 \, \text{N}\).

### Final Answer:
The frictional force between the object and the surface is \(10 \, \text{N}\).

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