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A body moves from point A to point B und...

A body moves from point A to point B under the action of a force varying in magnitude as shown in the force displacement graph. Find total work done by the force :

A

10 J

B

50 J

C

60 J

D

40 J

Text Solution

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The correct Answer is:
To find the total work done by the force as a body moves from point A to point B, we can follow these steps: ### Step 1: Understand the Force-Displacement Graph The force-displacement graph shows how the force varies with displacement. The work done by a force is equal to the area under the force-displacement curve. ### Step 2: Identify the Shape of the Area From the description, we can see that the area under the curve consists of a triangle and a trapezium. We need to calculate the area of these shapes to find the total work done. ### Step 3: Calculate the Area of the Triangle The triangle is formed from the origin (0,0) to the point (5,10). - The base of the triangle is 5 units (from 0 to 5 on the x-axis). - The height of the triangle is 10 units (from 0 to 10 on the y-axis). The area \(A_{triangle}\) can be calculated using the formula for the area of a triangle: \[ A_{triangle} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 5 \times 10 = 25 \text{ joules} \] ### Step 4: Calculate the Area of the Trapezium The trapezium is formed between the points (5,10) and (7,5). - The lengths of the parallel sides are 10 units (at x=5) and 5 units (at x=7). - The height of the trapezium is the difference in x-coordinates, which is \(7 - 5 = 2\) units. The area \(A_{trapezium}\) can be calculated using the formula for the area of a trapezium: \[ A_{trapezium} = \frac{1}{2} \times (\text{length of side 1} + \text{length of side 2}) \times \text{height} = \frac{1}{2} \times (10 + 5) \times 2 = \frac{1}{2} \times 15 \times 2 = 15 \text{ joules} \] ### Step 5: Calculate Total Work Done Now, we can find the total work done \(W\) by adding the areas of the triangle and the trapezium: \[ W = A_{triangle} + A_{trapezium} = 25 + 15 = 40 \text{ joules} \] ### Conclusion The total work done by the force as the body moves from point A to point B is **40 joules**. ---
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