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a body of mass 10 kg and radius of gyrat...

a body of mass 10 kg and radius of gyration 0.1 m is rotating about an axis. If angular speed is 10 rad/s, then angular momentum will be:

A

`1 kg m^(2)//s`

B

`0.1 kg m^(2)//s`

C

`100kg m^(2)//s`

D

`10kg m^(2)//s`

Text Solution

AI Generated Solution

The correct Answer is:
To find the angular momentum of a rotating body, we can use the formula: \[ L = I \cdot \omega \] where: - \( L \) is the angular momentum, - \( I \) is the moment of inertia, - \( \omega \) is the angular speed. ### Step 1: Calculate the Moment of Inertia (I) The moment of inertia \( I \) can be calculated using the formula: \[ I = m \cdot k^2 \] where: - \( m \) is the mass of the body, - \( k \) is the radius of gyration. Given: - Mass \( m = 10 \, \text{kg} \) - Radius of gyration \( k = 0.1 \, \text{m} \) Substituting the values: \[ I = 10 \, \text{kg} \cdot (0.1 \, \text{m})^2 \] Calculating \( k^2 \): \[ (0.1 \, \text{m})^2 = 0.01 \, \text{m}^2 \] Now substituting back: \[ I = 10 \, \text{kg} \cdot 0.01 \, \text{m}^2 = 0.1 \, \text{kg} \cdot \text{m}^2 \] ### Step 2: Calculate Angular Momentum (L) Now that we have the moment of inertia, we can calculate the angular momentum using the angular speed \( \omega \). Given: - Angular speed \( \omega = 10 \, \text{rad/s} \) Substituting the values into the angular momentum formula: \[ L = I \cdot \omega = 0.1 \, \text{kg} \cdot \text{m}^2 \cdot 10 \, \text{rad/s} \] Calculating: \[ L = 1 \, \text{kg} \cdot \text{m}^2/\text{s} \] ### Final Answer Thus, the angular momentum \( L \) is: \[ L = 1 \, \text{kg} \cdot \text{m}^2/\text{s} \] ---
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