Home
Class 12
PHYSICS
A proton , a deutron and alpha )- parti...

A proton , a deutron and `alpha )`- particle having the same kinetic energy are moving in circular trajectories in a constant magnetic field . If ` r_(p), r_(d) , and r_(alpha)` denote respectively the radii of the trajectories of these particles , then

A

`r_(alpha)=r_(p)ltr_(d)`

B

`r_(alpha)gtr_(d)gtr_(p)`

C

`r_(alpha)=r_(d)gtr_(p)`

D

`r_(p)=r_(d)=r_(alpha)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

A proton, a deuteron and an alpha - particle having the same kinetic energy are moving in circular trajectors in a constant magnetic field. If r_p, r_d and r_(alpha) denote respectively the radii of the trajectories of these particles then

Proton , deuton and alpha particle of same kinetic energy are moving in circular trajectories in a constant magnetic field. The radii of proton , deuteron and alpha particle are respectively r_(p), r_(d) and r_(alpha) . Which one of the following relation is correct?

A proton, an electron, and a Helium nucleus, have the same Kinetic energy. They are in circular orbits in a plane due to magnetic field perpendicular to the plane. Let r_(p), r_(e) and r_(He) be their respective radii, then

An electron, a proton and an alpha particle having the same kinetic energy are moving in circular orbits of radii r_(e),r_(p),r_(alpha) respectively in a uniform magnetic field B. The relation between r_(e),r_(p),r_(alpha) is:

A deuteron and an alpha particle having equal kinetic energy enter perpendicular into a magnetic field. Let r_(d) and r_(alpha) be their respective radii of circular path. The value of (r_(d))/(r_(alpha)) is equal to :

An electron, a proton, a deuteron and an alpha particle, each having the same speed are in a region of constant magnetic field perpendicular to the direction of the velocities of the particles. The radius of the circular orbits of these particles are respectively R_(e), R_(p), R_(d) and R_(alpha) It follows that