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If x(1) is the size of the magnified ima...

If `x_(1)` is the size of the magnified image and `x_(2)` is the size of the diminsghed image in lens displacement method, then the size of the object is

A

`sqrt(x_(1)x_(2))`

B

`x_(1)x_(2)`

C

`x_(1)^(2)x_(2)`

D

`x_(1)x_(2)^(2)`

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The correct Answer is:
A
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