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The wavelength of the light used in Youn...

The wavelength of the light used in Young's double slit experiment is `lambda`. The intensity at a point on the screen is I, where the path difference is `(lambda)/(6)`. If `I_(0)` denotes the maximum intensity, then the ratio of I and `I_(0)` is

A

0.866

B

0.5

C

0.707

D

0.75

Text Solution

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The correct Answer is:
D
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