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If cottheta+tantheta=x and sectheta-cos...

If `cottheta+tantheta=x` and `sectheta-costheta=y ,` prove that `(x^2y)^(2/3)-(x y^2)^(2/3)=1`

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`cot theta+ tan theta = (1+tan^2 theta)/(tan theta)=(sec^2 theta)/(tan theta)`
`x= cot theta + tan theta = 1/( sin theta cos theta)`
`sec theta - cos theta= (cos^2 theta)/( cos theta)=(sin^2 theta)/(cos theta)`
`y= sec theta- cos theta = (sin^2 theta)/(cos theta)`
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