The area of the triangle formed by `(a , b+c),(b , c+a)a n d(c , a+b)` is (a) `a+b+c` (b) `a b c` (c) `(a+b+c)^2` (d) `0`

Explanation

To find the area of the triangle formed by the points \((a, b+c)\), \((b, c+a)\), and \((c, a+b)\), we can use the formula for the area of a triangle given by three vertices \((x_1, y_1)\), \((x_2, y_2)\), and \((x_3, y_3)\):

\[ \text{Area} = \frac{1}{2} \left| x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) \right| \]

### Step-by-step Solution:

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