If S is the circumcentre, O is the orthocentre of `DeltaABC,` then `bar(SA) + bar(SB)+bar(SC)` equals

If S is circumcentre, O is orthocentre of DeltaABC , then vec(SA)+vec(SB)+vec(SC) =

If O is the circumcentre, 'H' is the orthocentre of triangle ABC, then show that bar(OA)+bar(OB)+bar(OC)=bar(OH)

If G is the centroid of DeltaABC then bar(GA)+bar(GB)+bar(GC)=

If S is the cirucmcentre, G the centroid, O the orthocentre of a triangle ABC, then vec(SA) + vec(SB) + vec(SC) is:

If S is the cirucmcentre, G the centroid, O the orthocentre of a triangle ABC, then vec(SA) + vec(SB) + vec(SC) is:

If G is centroid of the DeltaABC then bar(GA)+bar(BG)+bar(GC)=

If O is the circumcentre and O' the orthocenter of DeltaABC prove that (i) SA+SB+SC=3SG, where S is any point in the plane of DeltaABC . (ii) OA+OB+OC=OO' Where, AP is diameter of the circumcircle.