Match List with List II ans select the correct option :
`{:("list I" , "List II"),(" i, Bacillus thuringiensis " , 1" Production of chitinase"),("ii. Rhizobium meliloti" , 2." Scavenging of oil spills"),(" iii. Escherichia coli " , 3. " Incorporation of 'nif' gene"),("iv Peudomonas putida " , 4. " Production of Bt toxin "),("v. Trichoderma" , 5. "Production of human insulin"):}`

Options

A. i-2, ii-4, iii-1,iv-5, v-3
B. i-2,ii-4,iii-5,iv-1,v-3
C. i-4,ii-3,iii-5,iv-2,v-1
D. i-3,ii-4,iii-5,iv-1,v-2

Answer

To solve the matching question, we will analyze each organism in List I and identify its corresponding function in List II.

### Step-by-Step Solution:

1. **Bacillus thuringiensis**: This bacterium is known for its ability to produce a toxin (Bt toxin) that is harmful to certain insects. Therefore, it matches with option **4** (Production of Bt toxin).

2. **Rhizobium meliloti**: This bacterium is involved in nitrogen fixation in legumes. It is known to incorporate the 'nif' gene, which is essential for nitrogen fixation. Thus, it matches with option **3** (Incorporation of 'nif' gene).

3. **Escherichia coli**: This bacterium is widely used in biotechnology, particularly for the production of human insulin. Therefore, it matches with option **5** (Production of human insulin).

4. **Pseudomonas putida**: This bacterium is known for its ability to degrade environmental pollutants, including oil. Hence, it matches with option **2** (Scavenging of oil spills).

5. **Trichoderma**: This fungus is known for its ability to produce chitinase, an enzyme that breaks down chitin. Therefore, it matches with option **1** (Production of chitinase).

### Final Matching:
- i. Bacillus thuringiensis → 4. Production of Bt toxin
- ii. Rhizobium meliloti → 3. Incorporation of 'nif' gene
- iii. Escherichia coli → 5. Production of human insulin
- iv. Pseudomonas putida → 2. Scavenging of oil spills
- v. Trichoderma → 1. Production of chitinase

### Correct Option:
The correct sequence of matches is:
- 4, 3, 5, 2, 1

Thus, the correct answer is **Option C**.

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