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Specific volume of cylindrical virus par...

Specific volume of cylindrical virus particle is `6.02xx10^(-2) c c//g` whose radius and length `7 Å` and `10 Å` respectively. If `N_(A)=6.02xx10^(23)`, find molecular weight of virus:

A

15.4 Kg/mol

B

`1.54 xx 10^4` Kg/mol

C

`3.08 xx 10^4` Kg/mol

D

`3.08 xx 10^3` Kg/mol

Text Solution

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The correct Answer is:
A
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