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50 ml of a gaseous hydrocarbon (having 8...

50 ml of a gaseous hydrocarbon (having 85.7% carbon) at STP on combustion with oxygen gave 0.370 g of `CO_2, 0.142 g H_2 O` and an undetermined quantity of methane. The molecule formula of hydrocarbon will be:

A

`C_4 H_8`

B

`C_2 H_2`

C

`C_5 H_8`

D

`C_2 H_4`

Text Solution

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The correct Answer is:
A
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