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Amongst the species given below which ha...

Amongst the species given below which have shape similar to `XeOF_4`.
(I) `XeO_3`
(II) `IF_5`
(III) `PCI_5`
(IV) `SF_4`.

A

Only II

B

Only I

C

II and III

D

II and IV

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given species has a shape similar to `XeOF_4`, we need to analyze the molecular geometry of `XeOF_4` and compare it with the other species listed. ### Step-by-Step Solution: 1. **Determine the Structure of `XeOF_4`:** - Xenon (Xe) is the central atom. - It has 8 valence electrons (being a noble gas). - It forms 4 single bonds with fluorine atoms and 1 double bond with an oxygen atom. This results in 4 sigma bonds and 1 lone pair of electrons. 2. **Calculate the Steric Number:** - The steric number is calculated as the sum of sigma bonds and lone pairs. - For `XeOF_4`: - 4 sigma bonds (from 4 `Xe-F` bonds) + 1 lone pair = 5. - Therefore, the steric number is 5. 3. **Determine Hybridization:** - A steric number of 5 corresponds to `sp^3d` hybridization. 4. **Identify the Geometry:** - The geometry for `sp^3d` hybridization is trigonal bipyramidal. - However, with 1 lone pair, the shape becomes square pyramidal. 5. **Check the Other Species:** - **(I) `XeO_3`:** - Steric number = 3 sigma bonds + 1 lone pair = 4 (hybridization `sp^3`, shape is trigonal pyramidal). - **(II) `IF_5`:** - Steric number = 5 sigma bonds + 1 lone pair = 6 (hybridization `sp^3d^2`, shape is square pyramidal). - **(III) `PCl_5`:** - Steric number = 5 sigma bonds = 5 (hybridization `sp^3d`, shape is trigonal bipyramidal). - **(IV) `SF_4`:** - Steric number = 4 sigma bonds + 1 lone pair = 5 (hybridization `sp^3d`, shape is see-saw). 6. **Conclusion:** - The only species that has a shape similar to `XeOF_4` (which is square pyramidal) is `IF_5`. ### Final Answer: The species that has a shape similar to `XeOF_4` is **(II) `IF_5`**. ---
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