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Choose the coorect statement among the f...

Choose the coorect statement among the following:

A

`NO` is more stable than `NO^+`.

B

`NO^(2+)` is diamagnetic but `NO^+` is paramagnetic

C

`NO^-` is more stable than NO

D

`NO^+` is diamagnetic , `NO^-` is paramagnetic but `NO^+` is more stable than `NO^-`.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question, we need to analyze the statements regarding the stability and magnetic properties of the nitrogen-oxygen species: NO, NO+, and NO-. We will determine the bond order and magnetic properties of each species using Molecular Orbital Theory (MOT). ### Step-by-Step Solution: 1. **Determine the total number of electrons for each species:** - NO has 15 electrons (7 from N and 8 from O). - NO+ has 14 electrons (1 electron removed from NO). - NO- has 16 electrons (1 additional electron added to NO). 2. **Construct the molecular orbital diagram:** - For NO (15 electrons): - Fill the molecular orbitals in the order: σ1s, σ1s*, σ2s, σ2s*, σ2p_z, π2p_x, π2p_y, π2p_x*, π2p_y*, σ2p_z*. - The filling gives us: - Bonding: 10 electrons (σ1s: 2, σ2s: 2, σ2p_z: 2, π2p_x: 2, π2p_y: 2) - Antibonding: 5 electrons (σ1s*: 2, σ2s*: 2, π2p_x*: 1) - Bond Order = (Number of bonding electrons - Number of antibonding electrons) / 2 = (10 - 5) / 2 = 2.5. 3. **Calculate the bond order for NO+:** - For NO+ (14 electrons): - The filling will be similar to NO but with one less electron in the antibonding orbitals. - Bonding: 10 electrons (same as NO). - Antibonding: 4 electrons (σ1s*: 2, σ2s*: 2). - Bond Order = (10 - 4) / 2 = 3. 4. **Calculate the bond order for NO-:** - For NO- (16 electrons): - The filling will include one more electron in the bonding orbitals. - Bonding: 11 electrons (σ1s: 2, σ2s: 2, σ2p_z: 2, π2p_x: 2, π2p_y: 3). - Antibonding: 5 electrons. - Bond Order = (11 - 5) / 2 = 3. 5. **Determine the magnetic properties:** - NO has one unpaired electron, making it paramagnetic. - NO+ has no unpaired electrons, making it diamagnetic. - NO- has one unpaired electron, making it paramagnetic. 6. **Evaluate the stability based on bond order:** - Higher bond order indicates greater stability. - NO+ (bond order 3) is more stable than NO (bond order 2.5). - NO- (bond order 3) is also stable but less than NO+. ### Conclusion: The correct statement among the given options is: - NO+ is diamagnetic, NO- is paramagnetic, and NO+ is more stable than NO-.
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