The value of heat generated when 36.5 gm of HCI and 40 gm of NaOH reacts during neutralization

Options

A. 76.5 Kcal
B. 13.7 Kcal
C. More than 13.7 Kcal
D. 108 Kcal

Answer

To solve the problem of calculating the heat generated when 36.5 g of HCl and 40 g of NaOH react during neutralization, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reaction**:
The neutralization reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) can be represented as:
\[ \text{HCl} + \text{NaOH} \rightarrow \text{NaCl} + \text{H}_2\text{O} \]

2. **Calculate Moles of HCl**:
The molar mass of HCl is approximately 36.5 g/mol.
\[ \text{Moles of HCl} = \frac{\text{Mass of HCl}}{\text{Molar Mass of HCl}} = \frac{36.5 \text{ g}}{36.5 \text{ g/mol}} = 1 \text{ mol} \]

3. **Calculate Moles of NaOH**:
The molar mass of NaOH is calculated as follows:
\[ \text{Molar Mass of NaOH} = 23 \text{ g (Na)} + 1 \text{ g (H)} + 16 \text{ g (O)} = 40 \text{ g/mol} \]
Thus, the moles of NaOH are:
\[ \text{Moles of NaOH} = \frac{\text{Mass of NaOH}}{\text{Molar Mass of NaOH}} = \frac{40 \text{ g}}{40 \text{ g/mol}} = 1 \text{ mol} \]

4. **Determine Heat of Neutralization**:
The heat of neutralization for the reaction of a strong acid with a strong base is typically about -13.7 kcal per mole of water formed. Since both HCl and NaOH completely dissociate in solution, we can assume that 1 mole of HCl reacts with 1 mole of NaOH to produce 1 mole of water.

5. **Calculate Total Heat Released**:
Since we have 1 mole of HCl and 1 mole of NaOH, the heat released during the neutralization will be:
\[ \text{Heat Released} = -13.7 \text{ kcal} \]

### Final Answer:
The value of heat generated when 36.5 g of HCl and 40 g of NaOH react during neutralization is **-13.7 kcal**.

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